trigonometry problem please someone
help me
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sarveshyaul50:
please help
can you please solve it to squaring both the side
please
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Answer:
Step-by-step explanation:
Sec^6 x = ( sec^2 x)^3 =(tan^2 x+1)^3
=tan^6 x + 3 tan^4 x+ 3 tan^2 x + 1
=tan^6 x+ 3 tan^2 x(tan^2 x +1) + 1
= tan^6 x + 3 tan^2 x sec^2 x + 1
=1+3 sec^2 x x tan^2 x
thank u
I hope it helps....Your welcome
yes
That's good!!
please
instead of making cube can you solve it of making square
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