Question

Trigonometry: sec^2 22-cot^2 68 = 1

Answer 1

write cot^68 =tan^2 22
sec^2 22 - tan^22
it is of form
sec^2 theta - tan^2 theta=1
sec^2 22 - tan^2 22
=1 is answer
hence proved

Answer 2

sec² 22 - cot² 68 = 1

sec²(90-68) - cot²68 = 1

cosec² - cot² = 1  

1 = 1

L.H.S = R.H.S