Trigonometry.
Sec A - 1/ Sec A + 1 = 1 - Cos A / 1 + Cos A
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hope it is useful for u
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mark it brainliest dear if u like
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hey mate , here is the solution of this problem
secA-1/secA+1=( 1/cosA-1)/(1/cosa+1) [since SecA=1/cosA]
(1-cosA)/cosA/(1+cosA)/cosA [TAKING LCM]
it can be written as
cosA(1-cosA)/cosA(1+cosA)
cos A gets can canceled and we get
1-cosA/1+CosA
hope it helped you
secA-1/secA+1=( 1/cosA-1)/(1/cosa+1) [since SecA=1/cosA]
(1-cosA)/cosA/(1+cosA)/cosA [TAKING LCM]
it can be written as
cosA(1-cosA)/cosA(1+cosA)
cos A gets can canceled and we get
1-cosA/1+CosA
hope it helped you
mark as brainliest if it was help ful to you :-)
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