Question

Trigonometry !!!!

$= \frac{ { \sin }^{2}48 }{ { \cos }^{2}48 } + 1 = ?$
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Answer 1

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$= \frac{ { \sin }^{2}48 }{ { \cos }^{2}48 } + 1 = ?$

$= { \tan}^{2} 48 + 1$

$={\sec}^{2}\:48°$

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