trikon pqr sambahu hai jisame pqr= 25 terminal 3cm square 2 ho to trikon pqr ki parimiti kya?
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PQR is an equilateral Δ.
Area = √3/4 * a² = 25 √3 cm²
har ek bahu = a = 10 cm
Area = √3/4 * a² = 25 √3 cm²
har ek bahu = a = 10 cm
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