Question

Truck A of mass 6,000 kg is moving at 5 m/s. It is approaching truck B of mass 5,000 kg, which is stationary.
(a) Calculate the momentum of truck A.
(b) The trucks collide and their buffers compress and then they bounce off each other, remaining undamaged.

After the collision, truck B has a momentum of 27,000 kg m/s.
(i) Determine the impulse applied to truck B.
(ii) The trucks are ion contact for 0.60 s. : Calculate the average force on truck B.
(iii) Calculate the final speed of truck A.

Answer 1

Answer:

MV = M1V1 + M2V2

2000 * V = 500 * 4 + 1500 * 2

2000 V = 2000 + 3000

2000V = 5000

V = 5 / 2

MEANS THAT 2.5 M / S ^2

Explanation:apply this method

Answer 2

Answer:

2(a) 30000kg m/ s

2(b)(i) 27000kgm

2(b)(ii) 45000N

2(b)(iii) 0.50 m/s

Explanation:

2(a) momentum = mv

= 30000kg m/s

2(b)(i) impulse same as momentum change

27000kgm/ s

2(b)(ii) [2(a) / 2(b)(i)] / impulse

v= 3000/6000 = 0.50 m/s