Question

True or false:
A typical Mendelian dihybrid ratio of F generation is 3:1
2​

Answer 1

Dihybrid cross is a cross between two different lines/genes that differ in two observed traits. According to Mendel's statement, between the alleles of both these loci there is a relationship of completely dominant - recessive traits. In the example pictured to the right, RRYY/rryy parents result in F1 offspring that are heterozygous for both R and Y (RrYy).[1]

In this Dihybrid Cross, homozygous dominant traits were crossed with homozygous recessive traits. This particular cross always results in the phenotypic ratio of 1:0:0:0 meaning that the offspring will all have both dominant phenotypes but will be carriers of the recessive phenotypes.

In the name "Dihybrid cross", the "di" indicates that there are two traits involved (e.g. R and Y), the "hybrid" means that each trait has two different alleles (e.g. R and r, or Y and y), and "cross" means that there are two individuals (usually a mother and father) who are combining or "crossing" their genetic information.

This figure illustrates the process of dihybrid crosses between pea plants with multiple traits, their different generations, and their phenotypic ratio patterns

The Dihybrid cross is easy to visualize using a Punnett square of dimensions 16:

RY Ry rY ry

RY RRYY RRYy RrYY RrYy

Ry RRYy RRyy RrYy Rryy

rY RrYY RrYy rrYY rrYy

ry RrYy Rryy rrYy rryy

The rules of meiosis, as they apply to the dihybrid, are codified in Mendel's first law and Mendel's second law, which are also called the Law of Segregation and the Law of Independent Assortment, respectively.

For genes on separate chromosomes, each allele pair showed independent segregation. If the first filial generation (F1 generation) produces four identical offspring, the second filial generation, which occurs by crossing the members of the first filial generation, shows a phenotypic (appearance) ratio of 9:3:3:1, where:

the 9 represents the proportion of individuals displaying both dominant traits:

RRYY + 2 x RRYy + 2 x RrYY + 4 x RrYy

the first 3 represents the individuals displaying the first dominant trait and the second recessive trait:

RRyy + 2 x Rryy

the second 3 represents those displaying the first recessive trait and second dominant trait:

rrYY + 2 x rrYy

the 1 represents the homozygous, displaying both recessive traits:

rryy

The Dihybrid ratio=9:3:3:1

The genotypic ratios are: RRYY 1: RRYy 2: RRyy 1: RrYY 2: RrYy 4: Rryy 2: rrYY 1: rrYy 2: rryy 1.

1. the answer is false above is just about dihybrid ratio