Question

Try plz
1.A straight line has the equation 3x+5y =30
a)find x,when y= - 3
b)find y, when x =25

#plz solve this, I have exam tomorrow so fast​

Answer 1

Answer:

When y=-3

3x+5×-3=30

3x-15=30

3x=30+15=45

x=45/3 =15

When x=25 ,

3×25+5y=30

75+5y=30

5y=30-75

5y= -45

y= -9

hope this is helpful.....

Answer 2

Step-by-step explanation:

a) 3x+5y=30, y=-3

3x+5(-3)=30

3x-15=30

3x=30+15

3x=45

x=45/3

x=15

b)3x+5y=30, x=25

3(25)+5y=30

75+ 5 y=30

5y=30-75

5 y=-45

Y=-45/5

y=-9

THANK YOU