Question

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Answer 1

Given,
Total chocolate bars = 100

and total boxes = 10.

2 boxes with 10 choculate bars each = 2 × 10 = 20.

3 boxes with 7 choculate bars each = 3 × 7 = 21.

4 boxes with 10 choculate bars each = 4 × 10 = 40.

Here, 9 boxes containing 81 ( 20+21+40) Choculate bars.

ATQ, there are 100 choculate bars.

So, last box contains 100 - 81 = 19 Choculate bars.

Hence there were 19 Choculate bars in the last box.

:)

Answer 2

No.of boxes of chocolate =10
No.of bars of chocolate=100

2 boxes have 10 chocolate bars each=2×10=20 chocolate bars.

3 boxes have 7 chocolate bars each=3×7=21 chocolate bars.

4 boxes have 10 chocolate bars each=4×10=40 chocolate bars.

Remaining number of boxes=1
Total no.of chocolate bars in 9 boxes =20+21+40=81

No.of chocolate bars in the last 1 box=100-81=19

So, answer is 19

hope it helps you