Question

Try solving this

The answer must be detailed

Answer 1

let number of cows be x.
and number of chickens be 12-x.
now,total number of legs of a cow =4
and number of legs of a chicken =2

ATQ
4x+2(12-x)=28.
4x+24-2x=28
2x=28-24
2x=4
x=4/2=2

so,total number of cows =2.
and total number of chickens =12-2=10

Answer 2

No.of animals in the farm=12
No.of animal legs=28
Let the number of cows be x
Then the number of chickens be y
x+y=12-----(1)

Such cow has 4 legs and each chicken has 2 legs.
4x+2y=28------(2)

Multiply equation (1) with 2
2(x+y)=2(12)
2x+2y=24--------(3)

Compare equations (2)–(3)
4x+2y=28
2x+2y=24
_________
2x=4
x=2
No. of cows =2
x+y=12
2+y=12
y=12-2=10
no. of chickens=10

hope it helps you