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NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles InText Questions
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Class 7 Maths NCERT Solutions Chapter 7 Congruence of Triangles InText Questions
Try These (Page 140 -141)
Question 1.
In the figure, lengths of the sides of the triangles are indicated. By applying the SSS congruence rule, a state which pairs of triangles are congruent. In the case of congruent triangles, write the result in symbolic form:
Solution:
(i)
NCERT Solutions for Class 7 maths Integers chapter 6 img 43
In ΔABC and ΔPQR, we have
AB = PQ = 1.5 cm
BC = QR = 2.5 cm
CA = RP = 2.2 cm
By SSS criterion of congruence,
ΔABC ≅ ΔPQR
(ii)
NCERT Solutions for Class 7 maths Integers chapter 6 img 44
In Δ DEF and Δ LMN, we have
DE = MN = 3.2 cm
DF = LN = 3.5 cm
EF = LM = 3 cm
So, by SSS criterion of congruence,
Δ DEF ≅ Δ NML
(iii)
NCERT Solutions for Class 7 maths Integers chapter 6 img 45
In ΔABC and ΔPQR, we have
AC = PR = 5 cm
BC = PQ = 4 cm But AB ≠ QR
So, the SSS congruence rule is not applicable.
∴ Δ ABC and Δ PQR are not congruent.
(iv)
NCERT Solutions for Class 7 maths Integers chapter 6 img 46
In Δ ADB and Δ ADC, we have
AD = AD (Common)
DB = DC = 2.5 cm and, BA = CA = 3.5 cm
∴ By SSS criterion of congruence,
Δ ADB ≅ Δ ADC
Question 2.
In the figure, AB = AC, and D is the mid-point of BC.
NCERT Solutions for Class 7 maths Integers chapter 6 img 50
(i) State the three pairs of equal parts in ΔADB and ΔADC.
Solution:
Three pairs of equal parts in ΔADB and ΔADC are
AD = AD [Common]
AB = AC [Given]
DB = DC [∵ D is mid-point of BC]
(ii) Is ΔADB ≅ ΔADC ? Give reasons.
Solution:
By SSS criterion of congruence, .
ΔADB ≅ ΔADC
(iii) Is ∠B = ∠C? Why?
Solution:
Yes, ∠B = ∠C [∵ Corresponding parts of congruent triangles are equal]
Question 3.
In the figure, AC = BD and AD = BC. Which of the following statements is meaningfully written?
NCERT Solutions for Class 7 maths Integers chapter 6 img 51
(i)ΔABC ≅ ΔABD
Solution:
Statement ΔABC ≅ ΔABD is not meaningfully written as
AB = AB [Correct]
BC = BD [Incorrect]
CA = DA [Incorrect]
(ii)ΔABC ≅ ΔBAD
Statement ΔABC ≅ ΔBAD is written meaningfully as
AB = AB [Common]
BC = AD [Given]
CA = DB [Given]
Step-by-step explanation:
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