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Prove that L.H.S=R.H.S
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Answer:
LHS=
(1+1/tan2A)(1+1/cot2A)
(1+cot2A)(1+tan2A)
cosec2A * sec2A
(1/sin2A)(1/cos2A)
sin2A/cos2A
1/sin2A.cos2A
RHS=
1/cos2A-cos4A
1/cos2A(1-cos2A)
1/sin2A.cos2A
hence LHS=RHS=1/sin2Acos2A
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