Math, asked by Omkesh1, 1 year ago

Try to solve this question

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Answered by jaya1012
4
HELLO.......FRIEND!!

THE ANSWER IS HERE,


 =  >  \:  {x}^{2}  - 4 \sqrt{3} x + 3

 =  >  \:  {x}^{2}  + (3 - 2 \sqrt{3} )x + ( - 3 - 2 \sqrt{3} )x + 3

 =  >  \: x(x + 3 - 2 \sqrt{3} ) + ( - 3 - 2 \sqrt{3} )(x + 3 - 2 \sqrt{3} )

 =  >  \: (x + 3 - 2 \sqrt{3} )(x - 3 - 2 \sqrt{3})



:-)Hope it helps u.

jaya1012: plz mark as brainliest.
Omkesh1: Yes it really helped thank you
Answered by tejasri2
0
Hi Friend !!!

==================

x²- 4√3 x +3 = 0

x²+ (3-2√3) x +(-3-2√ 3) (x +3 -2√3)= 0

x (x + 3 - 2√3)+ (-3-2√3)(x+3-2√3) = 0

(x+3-2√3)(x-3-2√3) = 0

Hope it helps u :-)
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