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a²- (b-c)²
= [a-(b-c)] [a+(b-c)]
= (a-b+c) (a+b-c)
Here we used the formula
x²-y² = (x+y)(x-y)
Answered by
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a²-(b-c)² = (a+b-c)(a-b+c) ANSWER
Explanation:
Factorising a²-(b-c)²
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we know the algebraic identity:
x^2-y^2=>(x+y)(x-y)
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=[a+(b-c)][a-(b-c)]
= (a+b-c)(a-b+c)
Therefore,a²-(b-c)² = (a+b-c)(a-b+c)
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