Question

Tsum of a two digit number and the number obtained by reversing its digits is 21 find the number​

Answer 1

✪ $\huge{\red{\underline{\overline{\mathbf{Question}}}}}$ ✪

→Tsum of a two digit number and the number obtained by reversing it's digits is 121, and the digits differ by 3, find the number {Corrected Question}

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⇒Given:

• Sum of number and the reversed number=121
• Difference of number = 3

⇒To Find:

• The Original Number

⇒Solution:

⇒Let the Number = 10x+y

⇒$\therefore$ Number by reversing digits= 10y+x

⇒Let x > y and x-y=3 .........1

According to question-

⇒$10x+y+10y+x=121$

⇒$11x+11y=121$

⇒$11(x+y)=121$

⇒$x+y=\frac{121}{11}$

⇒$x+y=11$...........2

Adding 1 and 2 -

$x+{\cancel{y}}+x-{\cancel{y}}=11+3$

⇒$2x=14$

⇒$x=7$...........3

Using 3 in 1 -

⇒$x+y=11$

⇒$7+y=11$

⇒$y=4$

Original Number :-

⇒$\huge{\pink{\overbrace{\underbrace{74}}}}$

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Answer 2

Answer:

Tsum of a two digit number and the number obtained by reversing it's digits is 121, and the digits differ by 3, find the number {Corrected Question}

Step-by-step explanation:

→Tsum of a two digit number and the number obtained by reversing it's digits is 121, and the digits differ by 3, find the number {Corrected Question}

✪ \huge{\green{\underline{\overline{\mathbf{Answer}}}}}

Answer

✪

⇒Given:

Sum of number and the reversed number=121

Difference of number = 3

⇒To Find:

The Original Number

⇒Solution:

⇒Let the Number = 10x+y

⇒\therefore∴ Number by reversing digits= 10y+x

⇒Let x > y and x-y=3 .........1

According to question-

⇒10x+y+10y+x=12110x+y+10y+x=121

⇒11x+11y=12111x+11y=121

⇒11(x+y)=12111(x+y)=121

⇒x+y=\frac{121}{11}x+y=

11

121

⇒x+y=11x+y=11 ...........2

Adding 1 and 2 -

x+{\cancel{y}}+x-{\cancel{y}}=11+3x+

y

+x−

y

=11+3

⇒2x=142x=14

⇒x=7x=7 ...........3

Using 3 in 1 -

⇒x+y=11x+y=11

⇒7+y=117+y=11

⇒y=4y=4

Original Number :-

⇒\huge{\pink{\overbrace{\underbrace{74}}}}

74