Question

TUNTIJUHLATalsium
10. A carnot engine is operating between 100 degree Celsius and 50 degree Celsius. Its efficiency will be:
(A) 13.40%
(B) 15.20%
(C) 50%
(D) 100%​

Answer 1

$\eta = 1 - \dfrac{T2}{T1}$

$= > \eta = 1 - \dfrac{273 + 50}{273 + 100}$

$= > \eta = 1 - \dfrac{323}{373}$

$= > \eta = 1 - 0.86$

$= > \eta = 0.14$

$= > \eta \approx 14\%$

Hence , 13.40% is the answer