Question

TURN is a kite in which diagonals TR and NU intersect at point O. Find the value of x and y.

Answer 1

hey mate here is your answer
tu=Ur
33=7y-2
y=5
now
TN=nr
3x-5=22
X=9
hope it will help you
mark me brainliest

Answer 2

For the given kite TURN, the value of x and y is x = 9, y = 5.

Given,

Refer figure.

TURN is a kite.

Sides are given in the figure.

To find,

The value of x and y.

Solution,

Kite is defined as the type of quadrilateral, in which the length of 2 pairs of adjacent sides is equal.

As we can see from the figure, TURN is a kite, and its side lengths are given as

TN = 3x - 5,

NR = 22,

TU = 33, and,

UR = 7y - 2.

Here, the sides which are equal, are

TN = NR, and,

TU = UR.

To determine the value of x and y, we can equate the respective adjacent sides as above.

∵ TN = NR

⇒ 3x - 5 = 22

⇒ 3x = 22 + 5

⇒ 3x = 27

⇒ x = 27/3

⇒ x = 9.

Further,

∵ TU = UR

⇒ 7y - 2 = 33

⇒ 7y = 33 + 2

⇒ 7y = 35

⇒ y = 35/7

⇒ y = 5.

Therefore, for the given kite TURN, the value of x and y is x = 9, y = 5.

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