Question

TUTUN
U TUUIN
(C) SUVIV () 2000N
6. With a 10 Kg ofgun, 60 g bullet is fired at a velocity of 160m/s.
The backward thrust that the gun produces on firing will
have the velocity:
(a) 3.2 m/s (b) 1.9 m/s (c) 0.96 m/s (d) 2m/s
7 An obiect is dropped from the ton of a towar Llaw m.​

Answer 1

Answer:

Mass of gun ($\sf{m_{1}}$)= $\tt{10 kg}$

Mass of bullet ($\sf{m_{2}}$)= $\tt{60 g = 0.06 kg}$

Velocity of gun before firing ($\sf{u_{1}}$) = $\tt{0 m/s}$

Velocity of bullet before firing ($\sf{u_{2}}$) = $\tt{0 m/s}$

Velocity of gun after firing = $\sf{v_{1}}$

Velocity of bullet after firing ($\sf{v_{2}}$) = $\tt{160 m/s}$

According to the law of conservation of momentum :

$\tt{m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}}$

=》 $\tt{0 = 10v_{1} + 0.06(160)}$

=》 $\tt{(-9.6) = 10v_{1}}$

=》 $\tt{v_{1} = (-0.96) m/s}$

Answer: (c) 0.96 m/s backwards