Question

TUVINI
(a) A magnetic dipole is oscillating in a mag-
netic field obeying the following expression.
d²0 MB
dt? - TO
What is the time period of oscillation and
mention the nature of oscillation? 1% + y = 2​

Answer 1

Answer:

The time period of oscillation is

$T =2\pi\sqrt{ \frac{I}{MB}}$

And this is angular SHM

Explanation:

As we know that the torque on magnetic dipole due to external uniform magnetic field is given as

$\tau = M\times B$

$\tau = MB sin\theta$

If the dipole is displaced by small angle then we have

$I\alpha = - MB\theta$

$\alpha = - \frac{MB}{I}\theta$

so it is an angular SHM

here angular frequency is given as

$\omega = \sqrt{\frac{MB}{I}}$

so the time period of the motion is given as

$T =2\pi\sqrt{ \frac{I}{MB}}$

#Learn

Topic : Magnetic dipole moment

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