twelve balls are distributed among three boxes ,find the probability that the first box will contain 3 balls .... and also explain how we solve these type of prblms ....and sum stategy to make strong probability
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given,12 balls are distributed among 3 boxes & we hv to find the probability that the 1st box will contain 3 balls.
now,each ball can be put into any of the 3 mentioned boxes...
therefore , total number of ways in which 12 balls can be put into 3 boxes=3^12.
again,out of 12 given bals ,3 balls can be choosen in ^12c3 ways.
remainig,12-3=9..out of the other 2 boxes. it can be done in2^9 ways.
=^12c3*2^9ways.
hence,the probability that the 1st box will contain 3 balls=^12c3*2^9/3^12.
now,each ball can be put into any of the 3 mentioned boxes...
therefore , total number of ways in which 12 balls can be put into 3 boxes=3^12.
again,out of 12 given bals ,3 balls can be choosen in ^12c3 ways.
remainig,12-3=9..out of the other 2 boxes. it can be done in2^9 ways.
=^12c3*2^9ways.
hence,the probability that the 1st box will contain 3 balls=^12c3*2^9/3^12.
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