Question

twelve grams of sulfuric acid is dissolved in water to make 1200ml solution. the cpncentration in normality is​

Answer 1

Given:

Weight of H2SO4 = 122.5 gm

Volume = 1250 ml

Molar mass of H2SO4 = 98.07 gm/mol

No. of moles

equals fraction numerator Weight over denominator mol. space weight end fraction

space equals space fraction numerator 122.5 over denominator 98.07 end fraction

equals 1.2 space mol

Now,

Molarity v

equals space fraction numerator No. space of space mole over denominator Volume space of space solution space in space straight L end fraction

equals space fraction numerator 1.249 over denominator 1.250 end fraction

equals 1 space straight M

Normality = Molarity × No. of H+ ions

= 1×2 2 N

Therefore the normality of the solution is 2N.