Math, asked by Szasrar3747, 1 year ago

Twelve persons are arranged round the table. Find the total number of arrangements in which two particular persons amongst them are not to be side by side.

Answers

Answered by VEDULAKRISHNACHAITAN
0

Answer:

9.10!

Step-by-step explanation:

Hi,

Let us say the two particular persons be A and B.

Total number of arrangements in which two particular persons amongst

them are not to be side by side = Total number of ways of arranging 12

persons - Total number of ways  of arranging 12 persons in which A and B

sit side by side.

Total number of ways of arranging 12 persons round the table = (12 -1)!

= 11! ways

Total number of ways of arranging 12 persons in which A and B sit side by

side = Let us consider  both A and B together as one and find the number

of ways which is (11-1)!  but A and B can interchange among themselves

which could be done in 2 ways, hence total ways would be 2*10!.

Total number of arrangements in which two particular persons amongst

them are not to be side by side = 11! - 2.10!

= 10!(11 - 2)

= 9.10!

Hope, it helps !


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