Twelve resistors each of resistace 20 are connected in the circuit as
shown in figure. Find the current through the battery of e.m.f. 20 V
connected between points A and B.
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U have not mentioned if they are connected in series or parallel
so I'll solve for both the cases
1) PARALLEL
As all the resistors are equal
Rp=20/12=1.66
V=20
I=V/R=20/1.66=12A
2)SERIES
Rs=20×12=240 ohm
V=20
I=20/240=0.083A
I hope this helps ( ╹▽╹ )
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