twelve years ago the average age of a husband an wife was 20 years the average remain same today when they have 2 children what was the present age of the youngest child if they differ the age by 2 years?
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Answered by
2
Answer:
7 year old
Step-by-step explanation:
current age husband=h, wife=w.
12 years ago, avg:20. so (h-12)+(w-12)=20*2=40
hence, current, h+w=40+24=64
for avg of family to be the same h+w+C1+C2=20*4=80
hence 64+C1+C2=80
so C1+C2=16
now, c2-c1=2.. C2=c1+2
so
C1+C1+2=16
2*C1=14
C1=7....
Answered by
0
Answer:
12 years ago HUS and Wife Avg=20
current avg of family 4 members =20
avg=SUM OF THE OBSERVATION/ NO OF THE OBSERVATIOS
SUM=H+W+child+child/4
Hence-H+W+C+C=AVG×4
= 80
CURRENT AGE OF H+W= (20+12year=32)+20+12=32
64+C+C=80
EldC+younC=16
eldC-youC=2
- +
=2yc=14
=y=14/2=7
answer 7*
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