Question

twenty four is divided into two parts such that 7 times the first part added to 5 times the second part makes 146.find each part.​

Answer 1

Step-by-step explanation:

let 1st part be x and second part be y

ATQ

x+y=24

=>x=24-y......(let this be equation 1)

7x+5y=146......(let this be equation 2)

taking equation 1 and 2

7(24-y)+5y=146

168-7y+5y=146

168-2y=146

-2y=146-168

-2y = -22

y=22/2

y=11

from equation 1

x=24-y

x=24-11

x= 13

hence the 1st part is 13 and second part is 11

Answer 2

Let first part= x

and second part= y

A.t.q

x+y=24...........(1)

and

7x+5y=146............(2)

from (1)

y=24-x

fill value of y in (2)

7x+5(24-x)=146

7x+120-5x=146

2x=146-120

x=26/2

x=13

y=24-x

y=24-13

y=11

Answer⏬

One part=13

other part=11