Math, asked by karamvirsingh333, 13 hours ago

twenty - four is divided into two parts such that 7 times the first part added to 5 times the second part makes 146.find each part​

Answers

Answered by kipa41
0

Answer:

Hint:Here, let the first number be x, then the second number will be (24 – x). Also form mathematical equations using the second condition given in question. Solve the equation and find the value of x. Value of x obtained will be the first number and (24 – x) will be the second number.

Complete step by step answer:

Let the first part be x and second part be (24 – x). Now according to given condition,

7x+5(24–x)=1467x+5(24–x)=146

On simplifying

7x+120–5x=1467x+120–5x=146

On separating constants and variables

2x=146–120⇒2x=26⇒x=132x=146–120⇒2x=26⇒x=13

Therefore, the first number is 13 and the second number is (24 – x) = 24 – 13 = 11.

Verification:

Condition 1: Sum of two numbers should be 2424.

13+11=2413+11=24 (Satisfied)

Condition 2: 7 times the first part added to 5 times the second part makes 146146.

7 times the first number means 7×13=917×13=91.

And 5 times of second numbers means 5×11=555×11=55.

91+55=14691+55=146 (Satisfied)

Note: In these types of questions, form mathematical equations based on conditions given in question by letting numbers as x and y and make two equations con

Answered by NakshatraNShetty
0

Answer:

Let the two parts of the number be x and (24-x)

According to the question we can write as7x+5(24−x)=146

7x + 120 - 5x = 146

2x = 146 - 120

2x = 26

x = 26/2

⇒x=13

And also (24−x)=24−13=11

So the parts are 13 and 11

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