Question

Twenty years ago, the age age of father and his sonin the ratio of8:3.presently the father is only 127th times of his sonthen found out the personage of son
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Answer 1

Answer:

108.

Let the father's age be x and the son's age be y.

If the father's age was 3 times the son's age 18 years ago, then

x-18 = 3(y-18) (equation 1)

If the father's age now is twice the son's age now, then

x = 2y (equation 2)

Substitute equation 2 into equation 1:

2y-18 = 3(y-18)

2y-18 = 3y-54

.: y = 36 (adding [54–2y] to both sides & swapping sides)

Substitute y = 36 into equation 2 from above:

x = 2•36

= 72

.: The father is currently 72 years old and the son's current age is 36.

.: The sum of their ages is 36 + 72 = 108.

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