twice of angle a= thrice of angle c= 6 times of c
find abc
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these are the angles of a triangle?
it's not mention
yes
ohk
they are
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let 2 angle A = 3angle B = 6 angle C= x
2 angle A = x
angle A = X/2
angle B = X/3
angle C = X / 6
now,
angle A + angle B + angle C =180( angle sum property of triangle)
X/2+X/3+X/6 = 180
3x/6 + 2x/6 + x/6 = 180 ( LCM of 2 3 and 6 = 6)
6x/6 = 180
x = 180
angle A = x/2= 180/2 = 90 degree ans.
Angle B = x/3 = 180/3= 60 degree ans
Angle C = x/6 =180/6= 30 degree ans .
2 angle A = x
angle A = X/2
angle B = X/3
angle C = X / 6
now,
angle A + angle B + angle C =180( angle sum property of triangle)
X/2+X/3+X/6 = 180
3x/6 + 2x/6 + x/6 = 180 ( LCM of 2 3 and 6 = 6)
6x/6 = 180
x = 180
angle A = x/2= 180/2 = 90 degree ans.
Angle B = x/3 = 180/3= 60 degree ans
Angle C = x/6 =180/6= 30 degree ans .
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