Question

Twice the number decreased by 22 is 48. Find the number.​

Answer 1

Question Given :-

Twice the number decreased by 22 is 48

To find?

The number

Explanation:-

While finding any value which is unknown then "x" is a symbol of unknown number..There are some more which can be used instead of x such as "a", "b", "m", "n" etc..

Most probably use "x"

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Solution:-

Let the value of first number be x

And the value of Second number be 22

Also given that

Twice a number decreased by 22=2x-22

2x-22=48

Transporting 22 to RHS:-

2x=48+22

2x=70

x=$\dfrac{70}{2}$

x=35

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Answer 2

SOLUTION:

Given,

Twice a number decreased by 22 is 48

To Find :-

The number

Solution :

Let,

The required number be 'x'

According to question :-

Twice a number =

Twice a number decreased by 22 = 2x - 22

$\sf 2x - 22 = 48$

Transposing 22 to R.H.S :-

$\sf 2x = 48 + 22$

$\sf 2x = 70$

$\sf x = 70/2$

$\sf x = 35$

Therefore , required number = $\sf x = 35$

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