Question

Twice the number when decreased by 7 gives 4

Answer 1

Answer :

• The number is 5.5

Given :

• Twice the number when decreased by 7 gives 4

To find :

• The number

Solution :

⇥ let the number be x

Given,

• Twice the number when decreased by 7 gives 4 so,
• 2x - 7 = 4

Substituting the value

⇥ 2x - 7 = 4

⇥ 2x = 4 + 7

⇥ 2x = 11

⇥ x = 11/2

⇥ x = 5.5

Hence

The number is 5.5

Verification :

⇥ 2x - 7 = 4

⇥ 2(5.5) - 7 = 4

⇥ 11- 7 = 4

⇥ 4 = 4

Hence, Verified

Answer 2

Answer:

The required number is $5.5$.  

Step-by-step explanation:

Given : The condition is "Twice the number when decreased by 7 gives 4."

To find : The number =?

Solution :

• The given condition is "Twice the number when decreased by 7 gives 4."
• We have to find that number.

• Let, the number be $x$.
• To find the number, we have to frame an algebraic equation according to given condition.

• According to given condition, the equation becomes,

          $2x-7=4$

• Transpose $7$ to other side, we get

            ∴ $2x=4+7$

             ∴ $2x=11$

             ∴ $x=\frac{11}{2}$

             ∴ $x=5.5$

• ∴ The required number is $5.5$.