twice the son's age in years, is added to the father's age, the sum is 70. But, if twice the father's age is added to the son's age, the sum is 95. Find their ages.
Answers
Answered by
1
let the son's age be x and father's age be y.according to the question,
2x+y=70
2y+x=95
x=70-y/2
put in 2nd equation
2y+(70-y/2)=95
2y+70-y/2=95
(4y+70-y)/2=95
70+4y-y=95*2
70+3y=190
3y=190-70
3y=120
y=120/3
y=40
father's age=40
2x+40=70
2x=70-40
2x=30
x=30/2
x= 15
son's age=15
plz mark it as the brainiest answer
2x+y=70
2y+x=95
x=70-y/2
put in 2nd equation
2y+(70-y/2)=95
2y+70-y/2=95
(4y+70-y)/2=95
70+4y-y=95*2
70+3y=190
3y=190-70
3y=120
y=120/3
y=40
father's age=40
2x+40=70
2x=70-40
2x=30
x=30/2
x= 15
son's age=15
plz mark it as the brainiest answer
anvi555:
my answer is correct?
Answered by
2
2x + y = 70
x + 2y = 95
x = 15
y = 40
x + 2y = 95
x = 15
y = 40
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