Question

Two 10 kg wts are attached at the two ends of a string which passes over a pulley

Answer 1

Answer:

Explanation:m1 = 2kg

m2= 3kg

Now,

T= (2m1 × m2 / m1 × m2 )g

m1 = 2kg

m2= 3kg

Now,

T= (2m1 × m2 / m1 × m2 )g

= (2 ×2 ×3/ 2+3 )g

= 12/5 g

a = (m2 - m1 / m1+ m2) g

= (3-2/3+2)g

= g/5

= (2 ×2 ×3/ 2+3 )g

= 12/5 g

a = (m2 - m1 / m1+ m2) g

= (3-2/3+2)g

= g/5