Question

.Two 2-digit numbers have hcf13 and lcm is 156. Which of the following is the largest number​

Answer 1

Answer:

Step-by-step explanation:

Assuming number are A and B,The HCF of both the numbers is 13 so both are multiple of 13

Assume A=13 and B=13y

Sum of numbers=13x+13y=13*( x+y)=156

so x+y=156/13=12

x+y=12

Assuming that A and B both are positive integers so x and y both are also positive integers

And the possible value of (x,y) are : (1,11),(2,10)(3,9),(4,8),(5,7)(6,6)

Thus 6 number of such pairs are possible.

Answer 2

Answer:

Sum of numbers=13x+13y=13*( x+y)=156

so x+y=156/13=12

x+y=12

Step-by-step explanation: