Question

Two 20V Batteries are connected in series to two resistors which are in parallel. Values of the resistors are 20 and 25 ohms. Draw the circuit diagram for this scenario. Find the current flowing through the circuit.

Answer 1

Answer:

Answer

The current in the 10Ω resistance is

i

1

=

R

1

+R

2

R

2

i=

20+10

(20)×(6)

=4A

The current in the 20Ω resistor is

i

2

=

R

1

+R

2

R

1

i=

10+20

10×6

=2A

Or

emf across 10Ω resistor

V

1

=i

1

×10

emf across 20Ω resistor

V

2

=i

2

×20

Since i

1

+i

2

=6A and V

1

=V

2

, we have i

1

=4A

i

2

=2A