Question

two 40ohm resistors and a 200 resistor connect in parallel with 12 v power supply their effective resistance and current thorough each resister . what the current flowing through the supply. ​

Answer 1

Answer:

A resistance R is connected in series with a parallel circuit comprising of resistances of 4Ω and 6Ω respectively. When the applied voltage is 15V, the power dissipated in 4Ω resistor is 36W, calculate R?

Power across 4Ohm=[math]\frac{V_4^2}{4}=36W[/math]

So, [math]V_4=12V[/math]

Since 4 and 6 Ohm are parallel, so

Req.=2.4 Ohm

As 4 and 6 Ohm are parallel, the voltage across them is same=12V. So, current through parallel circuit

[math]I=\frac{12}{2.4}=5A[/math]

As this circuit is in series with R, so same current flows through R i.e, 5A.

Potential difference across R is (15–12)=3V as parallel branch has 12V and source is 15V.

So, [math]R=\frac{15–12}{5}=0.6Ω[/math]

Explanation:

I hope this helps you.