Physics, asked by NidhaNeenu9464, 11 months ago

Two absolute scale A and B have triple points water defined as 200A and 350B. What is the relation between A and B

Answers

Answered by pradip4970saha
3

Answer:

Triple point of water on absolute scaleA, T1 = 200 A

Triple point of water on absolute scale B, T2 = 350 B

Triple point of water on Kelvin scale, TK = 273.15 K

The temperature 273.15 K on Kelvin scale is equivalent to 200 A on absolute scale A.

T1 = TK

200 A = 273.15 K

∴ A = 273.15/200

The temperature 273.15 K on Kelvin scale is equivalent to 350 B on absolute scale B.

T2 = TK

350 B = 273.15

∴ B = 273.15/350

TA is triple point of water on scale A.

TB is triple point of water on scale B.

∴ 273.15/200 × TA = 273.15/350 × TB

Therefore, the ratio TA : TB is given as 4 : 7.

Answered by Harsh8557
26

Answer:

  • T_{A} = \dfrac{200}{350}T_{B}

Explanation:

  • The triple point of water on absolute scale A, T_{1} = 200 A
  • The triple point of water on absolute scale B, T_{B} = 350 B
  • The triple point of water on the Kelvin scale, T_{K}= 273.15 K

The temperature of 273.15 K on the Kelvin scale is equivalent to 200 A on absolute scale A.

\implies\:\:\:T_{1}= T_{K}

\implies\:\:\:200A = 273.15 K

\implies\:\:\: A = \dfrac{273.15}{200}

The temperature of 273.15 K on the Kelvin scale is equivalent to 350 B on absolute

scale B.

\implies\:\:\:T_{2}= T_{K}

\implies\:\:\:350 B = 273.15

\implies\:\:\:B = \dfrac{273.15}{350}

T_{A} is the triple point temperature of the water on scale A.

T_{B} is the triple point temperature of the water on scale B.

\therefore \: \dfrac{273.15}{200}\times T_{A} = \dfrac{273.15}{350}\times T_{B}

\implies\:\:\:T_{A}= \dfrac{200}{350}T_{B}

The ratio T_{A}:T_{B} is given as 4:7

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