Question

Two adjacent angle of a paralleogram are in the ratio 3:8 and its perimeter is 110 cm. Find the sides of the parallelogram

Answer 1

heya

written explanation-

Let, ABCD be the parallelogram.

Given : Two adjacent sides of the parallelogram are in ratio 3:8.

And,

perimeter of the parallelogram is 110cm

AD = 3x cm

DC = 8x cm

AD = BC and DC = AB [  Opposite sides of parallelogram are equal ]

So,

Perimeter of the parallelogram

=> AB + BC + DC + AD = 110 cm

=> 8x + 3x + 8x + 3x = 110

=> 22x = 110

=> x =

=> x = 5

So,

AB = 8x = 8*5 = 40 cm

BC = 3x = 3*5 = 15 cm

DC = 8x = 8*5 = 40 cm

AD = 3x = 3*5 = 15 cm

U can also refer to the pic

Answer 2

Answer:

Let ABCD be the parallelogram

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal]

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110 22x= 110

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110 22x= 110 x= 110/22

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110 22x= 110 x= 110/22x=5

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110 22x= 110 x= 110/22x=5 AB= 8x × 5= 40 cm

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110 22x= 110 x= 110/22x=5 AB= 8x × 5= 40 cmBC= 3x =3×5=15cm

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110 22x= 110 x= 110/22x=5 AB= 8x × 5= 40 cmBC= 3x =3×5=15cmDC= 8x=8×5= 40 cm

Let ABCD be the parallelogram(Given) : two adjacent sides of the parallelogram are in ratio 3:8 perimeter of the parallelogram is 110 cm AD = 3x cm DC = 8x AD= BC and DC= AB [ opposite sides of parallelogram are equal] perimeter of parallelogram= AB+BC+DC+AD= 110 8x+3x+8x+3x+= 110 22x= 110 x= 110/22x=5 AB= 8x × 5= 40 cmBC= 3x =3×5=15cmDC= 8x=8×5= 40 cmAD=3x=3×5= 15cm