Question

two adjacent angle of parallelogram are 3x+4 and 3x-16. find the value of x also find each angle of parallelogram​

Answer 1

3x+4+3x-16=180

(sum of adjacent angles in parallelogram is 180°)

6x-12=180

6x=180+12

X=192/6

X=32

first angle =3x32+4

=96+4

=100°

second angle=3x32-16

=96-16

=80°

Answer 2

In parallelogram ABCD
AD parallel to BC and AB is transversal
angle A +angle B = 180° ( Co- interior angles)
3x+4+3x-16 =180°
6x-12=180°
6x=192
x=32°
then
angle A = 100°
angle B =80°