Question

two adjacent angles of a parallelogram are 2 X + 9 degree &4x-3degree .find tge angles





please please tell me​

Answer 1

Answer:

Here is the answer,

Since adjacent angles of a parallelogram are supplementary (180)

2x+9+4x-3=180

= 6x+6=180

6x=180-6

6x= 174

X= 174/6=29

So 2x+9= 2*29+9=67

4x-3=4*29-3=113

Hope it helps you!!

I thinks it is right

pls mark me as brainliest

Answer 2

let angles 2x+9 be A and 4x-3 be B

we know that the sum of supplementary angles is 180°

therefore,

(2x+9°)+(4x-3)°=180°

2x+9+4x-3=180

6x+6=180

6(x+1)=180

x+1=30

x=29

put x =29 in the value of A and B

2(29)+9=A

58+9=A

A=67°

B=4x-3

B=4(29)-3

B=116-3

B=113

And the opposite angles are same

A=C=67°

B=D=113°

hope it helps uh