Question

two adjacent angles of a parallelogram are (3x-4) degree and (3x+16) degree. Find the measure of each of these angles

Answer 1

Sum of adjacent angles of a parallelogram = 180°
(3x - 4) + (3x + 16) = 180
                 6x + 12 = 180
                        6x = 168
                          x = 28
  3x - 4 = 80
3x + 16 = 100
Therefore, the angles are 80°, 100°, 80°, 100°

Answer 2

The adjacent sides of a parallelogram are co-interior angles hence their sum will be 180 degrees
(3x-4)+(3x+16)=180
3x-4+3x+16=180
6x+12=180
6x=180-12
x=168/6
x=28
Hence
Angle 1 =3x-4=84-4=>80 degree
Angle 2=3x+16=84+16=>100 degree
Angle 1=Angle 4 (opposite angles )
Angle 2=Angle 3(opposite angles)