two adjacent angles of a parallelogram are (5x+65) degrees and (85-2x)degrees find the measure of each angle of a parallrlogram
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Answered by
196
We know that opposite angles of parallelograms are equal
And its sum of all the sides = 180
(5x + 65)+(85-2x)=180
5x-2x+65+85=180
3x+150=180
3x=180-150=30
3x=30
X=30/3=10
1st adjacent side = 5x+65=5*10+65=50+65=115
2nd adjacent side = 85-2x=85-2*10=85-20=65
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And its sum of all the sides = 180
(5x + 65)+(85-2x)=180
5x-2x+65+85=180
3x+150=180
3x=180-150=30
3x=30
X=30/3=10
1st adjacent side = 5x+65=5*10+65=50+65=115
2nd adjacent side = 85-2x=85-2*10=85-20=65
HOPE IT HELPS U. MARK AS BRAINLIEST PLZZ.
Answered by
14
Given:
Two adjacent angles of a parallelogram are (5x+65)° and (85-2x)°
To Find:
The measure of each angle of a parallelogram.
Solution:
We know that,
opposite angles of a parallelogram are equal
sum of adjacent angles = 180°
So,
(5x + 65)° + (85-2x)° = 180°
5x - 2x + 65° + 85° = 180°
3x + 150° = 180°
3x = (180-150)° = 30°
3x = 30°
x = (30/3)° = 10°
Putting the value of x = 10° in the equations, we get
1st adjacent side = 5x + 65 = 5*10 + 65 = 50 + 65 = 115°
2nd adjacent side = 85 - 2x = 85 - 2*10 = 85 - 20 = 65°
Hence, measure of each angle of the parallelogram is 115°, 65°, 115° and 65°.
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