Question

two adjacent angles of a parallelogram is in ratio of 3:7 find all the angles

Answer 1

Given :

• Let the common ratio be x

➡ As we know that,

• Sum of adjacent angles of parallelogram =180 degree

To find :

➡ All the angles =?

Properties :

• Sum of adjacent angles of parallelogram =180 degree

• Opposite sides of parallelogram are equal.

Solution :

According to given conditions :

$\implies \bf \: 3x + 7x = 180 \degree \\ \\ \implies \bf \: 10x = 180 \degree \\ \\ \implies \bf \: x = \frac{180}{10} = 18 \degree \\ \\ \implies \boxed{ \bf{x = 18 \degree}}$

Others angles are :

$\bullet \bf \: 3x = 3 \times 18 \degree = 54 \degree \\ \\ \bullet \bf \: 7x = 7 \times 18 \degree = 126 \degree$

The angles of parallelogram are 18,54, and 126 degree

Answer 2

Given :

Let the common ratio be x

➡ As we know that,

• Sum of adjacent angles of parallelogram =180 degree

To find :

➡ All the angles =?

Properties :

• Sum of adjacent angles of parallelogram =180 degree

• Opposite sides of parallelogram are equal.

Solution :

According to given conditions :

$\implies \bf \: 3x + 7x = 180 \degree \\ \\ \implies \bf \: 10x = 180 \degree \\ \\ \implies \bf \: x = \frac{180}{10} = 18 \degree \\ \\ \implies \boxed{ \bf{x = 18 \degree}}$

$⟹3x+7x=180° \\ </p><p>⟹10x=180° \\ </p><p>⟹x= 18°$

Others angles are :

$\bullet \bf \: 3x = 3 \times 18 \degree = 54 \degree \\ \\ \bullet \bf \: 7x = 7 \times 18 \degree = 126 \degree\ \\ </p><p>∙3x=3×18°=54° \\ </p><p>∙7x=7×18°=126°$

The angles of parallelogram are 18,54, and 126 degree