Question

Two adjacent angles of a parallelogram<br />are (3y +10°) and (3y-4°):. Find the<br />measures of all angles of the<br />parallelogram.​

Answer 1

Answer:

Sum of adjacent angles of parallelogram is equals to 180 degree

now (3y+10)+(3y-4)=180

=6y+6=180

=6y=174

=y=29 degree

hence angles of parallelogram are

3y+10,3y-4 i.e 97,83

Answer 2

Let ABCD be a //gm in which ,

Angle A = Angle C = 3y+10 ...(i)...

Angle B = Angle D = 3y- 4 ...(ii) ...

•°• Angle A + Angle B =180°

=> 3y+10 + 3y-4 =180°

=> 6y+6 = 180°

=> y+1=30 (Divided by 6)

=> y = 29°

Put in (i) and (ii)

•Angle A = Angle C = 3y+10

=3(29)+10 =97°

•Angle B = Angle D = 3y- 4

= 3(29)-4 = 83°

Hence, all angles of //gm ABCD are :- Angle A = Angle C=97°

all angles of //gm ABCD are :- Angle A = Angle C=97°Angle B = Angle D=83°

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