two adjacent angles of a rhombus are 3 x minus 40 degree and 2 X + 20 degree find the measurement of the greater angle
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Answered by
68
Here , 2x+20+3x-40= 180 degree.
(as it is a rhombus , opposite side will be parallel and it's adjacent side will be a transversal i.e. interior angle on the same side of transversal are supplementary)
5x-20=180
5x=200
x=200/5
x=40degree
3x-40=120-40=80 degrees
2x+20=80+20=100degrees
Therefore , the measure of the bigger angle is 100 degree...
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(as it is a rhombus , opposite side will be parallel and it's adjacent side will be a transversal i.e. interior angle on the same side of transversal are supplementary)
5x-20=180
5x=200
x=200/5
x=40degree
3x-40=120-40=80 degrees
2x+20=80+20=100degrees
Therefore , the measure of the bigger angle is 100 degree...
If you find it helpful please mark it brainliest .....
Thank You
Answered by
21
In a rhombus, sum of adjacent angles =180,then, 3x-40+2x+20=180then x=40then greater angle is 2x+20=2*40+20=100
yaseerkhan0019:
thanks bro
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