Question

Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between
longer sides is 12 cm, find the distance between shorter sides.

**steps required**​

Answer 1

Step-by-step explanation:

The length of side 24cm

Its corresponding height is 12cm

The area of parallelogram is 24×12=288cm

The length of another side is 18cm

The area of parallelogram is 288cm

Its corresponding height is

288/18

=16cm

Answer 2

Given :-

• Adjacent sides parallelogram = 24cm & 18cm
• Distance between longer sides = 12cm

We need to find :-

• Distance between shorter sides = ?

Solution :-

Let the distance between the shorter side be ‘x’

Lets take a parallelogram ABCD with base AB & base BC . However it has two bases so there will be two heights & let point E be the mid point of AB & point F be the mid point of BC . So the height will be DE & DF

And here

• DE is the distance between longer sides = 12
• DF is the distance between shorter sides = x

Now as we know that

Area = Base × Height

→ Area = AB × DE

→ Area = 24 × 12

→ Area = 288cm² ....eq(1)

♦ Area = BC × DF

♦ Area = 18 ( x )

♦ Area = 18x cm² ….eq(2)

By eq(1 & 2)

⇒ 288 = 18x

⇒ x = 288/18

⇒ x = 16cm = distance between shorter sides

Hence , distance between shorter sides = 16cm