Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between longer sides is 12 cm, find the distance between shorter sides.
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Area of a parallogram=base×height………….(1)
Area of a parallogram=base×height………….(1)Area of a parallogram=24×12 sq.cm
Area of a parallogram=base×height………….(1)Area of a parallogram=24×12 sq.cmLet distance between shorter sides=h cm
Area of a parallogram=base×height………….(1)Area of a parallogram=24×12 sq.cmLet distance between shorter sides=h cmAlso area of parallogram=18×h sq.cm
Area of a parallogram=base×height………….(1)Area of a parallogram=24×12 sq.cmLet distance between shorter sides=h cmAlso area of parallogram=18×h sq.cm18×h=24×12
Area of a parallogram=base×height………….(1)Area of a parallogram=24×12 sq.cmLet distance between shorter sides=h cmAlso area of parallogram=18×h sq.cm18×h=24×12h=(24×12)/18=16 cm.
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Let take 24 cm as the base of parallelogram, then its height is 12 cm.
We know that,
Area of parallelogram = base × height
= 24 × 12 = 288 cm2
Let’s consider d cm to be the distance between the shortest sides.
∴ Area of parallelogram = (18 × d) cm2
18 × d = 288
⇒ d = 288/18 = 16 cm
Therefore, the distance between the shorter sides is 16 cm.
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