Question

Two adjacent sides of a parallelogram are 30m and 14 m and the diagonal joining yhe end points of these sides is 40 m the area of parallelogram is

Answer 1

Answer:

Step-by-step explanation:

let ABCD be the given parallelogram  

area of parallelogram ABCD = 2 x (area of triangle ABC)  

now a = 30m, b = 14m and c = 40m

s=1/2 x (30+14+40) = 42  

 

Area of triangle ABC = √[s(s−a)(s−b)(s−c)

 

=√ [42(12)(28)(2)]= 168sq m  

area of parallelogram ABCD = 2 x 168 = 336 sq m