Two adjacent sides of a parallelogram are 30m and 14 m and the diagonal joining yhe end points of these sides is 40 m the area of parallelogram is
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Step-by-step explanation:
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC = √[s(s−a)(s−b)(s−c)
=√ [42(12)(28)(2)]= 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
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