Question

Two adjacent sides of a rectangle are 3x^2 -5y^2 and 7x^2 -xy. Find its perimeter

Answer 1

Adjacent sides in rectangle are lenght and base

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Perimeter of rectangle =2(length + breadth)


Perimeter =2(3x²-5y²+7x²-xy)

Perimeter =2(10x² -5y²-xy)

Perimeter =20x²-10y² -2xy



I hope this will help you


-by ABHAY

Answer 2

The perimeter of rectangle $=2(10x^{2} -5y^{2}-xy)$ or $20x^{2} -10y^{2}-2xy$.

Step-by-step explanation:

We have,

The two adjacent sides of a rectangle = $3x^{2} -5y^{2}$ and $7x^{2} -xy$

Here, length(l) $=3x^{2} -5y^{2}$ and breadth(b) $=7x^{2} -xy$

To find, the perimeter of rectangle = ?

We know that,

The perimeter of rectangle =2(Length + Breadth)

$=2(3x^{2} -5y^{2}+7x^{2} -xy)$

$=2(10x^{2} -5y^{2}-xy)$

$=20x^{2} -10y^{2}-2xy$

Hence, the perimeter of rectangle$=2(10x^{2} -5y^{2}-xy)$] or $20x^{2} -10y^{2}-2xy$.