Two adjacent sides of a rectangle are 3x2 – 5y2 and 7x2 – xy. Find its perimeter.
Answers
Answered by
45
Answer:
20x²-10y²-2xy
Step-by-step explanation:
It's perimeter=2(l+b)
=2(3x²-5y²+7x²-xy)
=2(10x²-5y²-xy)
=20x²-10y²-2xy(Ans)
Answered by
23
Answer:
Adjacent sides in rectangle are lenght and base
Perimeter of rectangle =2(length+breadth)
Perimeter =2(3x²−5y²+7x²−xy)
Perimeter =2(10x²−5y²−xy)
Perimeter =20x²−10y²−2xy.
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