two adjacent sides of parallelogram are 15cm and 10cm. if the distance betewen the longer sides is 8cm find the (i)area of parallelogram (ii) the distance between the shorter sides.
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117
area of ||gm = base × height =15×8=120
as area = base × height =10 ×distance b/w shorter sides
10×distance=120
distance b/w shorter sides =120/10=12cm
if it really helped you , then please brainiest.
as area = base × height =10 ×distance b/w shorter sides
10×distance=120
distance b/w shorter sides =120/10=12cm
if it really helped you , then please brainiest.
PrateekStar1:
your wlcm
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62
Area of parallelogram = base × height
Taking AB as base
Area= 15×8= 120cm^2
NOW for distance between shorter sides which is equal to the height corresponding to base BC
Area =120
Base ×height =120
10 × height = 120
Height = 12 cm
Taking AB as base
Area= 15×8= 120cm^2
NOW for distance between shorter sides which is equal to the height corresponding to base BC
Area =120
Base ×height =120
10 × height = 120
Height = 12 cm
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